I am trying to pass the ListView or the GridView as a ConverterParameter However, in the Converter routine the parameter is coming as a type string
Below is the part of the XAML List view and the Converter class.
Any help greatly appreciated. Thanks!!!
<ListView Name="SeqDtStDataListView1" Grid.Row="1"
DataContext="{Binding Path=DisplayDT[0], Converter ={StaticResource
CNVToColumn},ConverterParameter=?????}"
VerticalContentAlignment="Stretch" VerticalAlignment="Stretch"
HorizontalAlignment="Stretch"
SelectionChanged="SEQDatalistview_SelectionChanged" Margin="5">
<ListView.View >
<GridView x:Name="SeqDtStDataGridView1"/>
</ListView.View>
</ListView>
Converter:
namespace MFTest.Converters
{
public class CNVToColumn : IValueConverter
{
public object Convert(object value,
Type targetType,
object parameter,
System.Globalization.CultureInfo culture)
{
DataTable dt = (DataTable)value;
GridView GV = (GridView)parameter; <========= fail here ===========
if (dt != null && GV != null)
foreach (var colum in dt.Columns) // Binding the Columns
{
DataColumn dc = (DataColumn)colum;
GridViewColumn column = new GridViewColumn();
column.DisplayMemberBinding = new Binding(dc.ColumnName);
column.Header = dc.ColumnName;
GV.Columns.Add(column);
}
return null;
}
public object ConvertBack(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
{
throw new NotImplementedException();
}
}
}
You could use
ConverterParameter={Binding ElementName=[insert x:Name of grid view]}
Although IMHO I'd reconsider the need - do you really need to pass a UIControl as a Converter parameter?