How to create a System.Drawing.Color from its hexadecimal RGB string?

Question

I want to create a System.Drawing.Color from a value like #FF00FF or FF00FF without needing to write code for that. There is any .NET built-in parser for that?

Answer 1

ColorTranslator.FromHtml("#FF00FF");

Answer 2

The FromName method worked for me

System.Drawing.Color.FromName("#FF00FF");

Answer 3

It is rather easy when you use the Convert-Class. The ToInt32 function has an overload with a second parameter which represents the base the string is in.

using System.Drawing

Color yourColor = Color.FromARGB(Convert.ToInt32("FF00FF", 16));

Answer 4

Use the ColorConverter class:

var converter = System.ComponentModel.TypeDescriptor.GetConverter( typeof( Color ) );
color = converter.ConvertFromString( "#FF00FF" );

This can also convert from the standard named colors e.g. ConvertFromString( "Blue" )

See here for a discussion of the standard .NET type conversion mechanisms.

Answer 5

You can use the System.Drawing.ColorTranslator static method FromHtml.

use:

System.Drawing.ColorTranslator.FromHtml("#FFFFFF");

Answer 6

If the color you want to use is a constant, in C# use System.Drawing.Color.FromArgb (0xFF00FF). That is slightly faster than System.Drawing.Color.FromName or System.Drawing.Color.FromHtml, since the parsing from a string to integer is done at compile time rather than at runtime.