I have
filtered_symbolic_path = ['A', 'B', 'C', 'D', 'B', 'C']
filtered_symbolic_path_times = [ 3, 4, 5, 6, 5, 3]
Here,
A=3, B=4 ,C=5, D =6, B=5. C=3
I want a dictionary like,
time_per_screen{A:3,B:9,C:8,D:6}
I have
filtered_symbolic_path = ['A', 'B', 'C', 'D', 'B', 'C']
filtered_symbolic_path_times = [ 3, 4, 5, 6, 5, 3]
Here,
A=3, B=4 ,C=5, D =6, B=5. C=3
I want a dictionary like,
time_per_screen{A:3,B:9,C:8,D:6}
filtered_symbolic_path = ['A', 'B', 'C', 'D', 'B', 'C']
filtered_symbolic_path_times = [ 3, 4, 5, 6, 5, 3]
time_per_screen = {}
for a, b in zip(filtered_symbolic_path, filtered_symbolic_path_times):
time_per_screen[a] = b
edit: you should make sure that the 2 lists are the same length...I'll leave that for you to do. there's a neat tool called google...it's been around for a while now ;)
Try doing this:
filtered_symbolic_path = ['A', 'B', 'C', 'D', 'B', 'C']
filtered_symbolic_path_times = [ 3, 4, 5, 6, 5, 3]
time_per_second = {}
for a, b in zip(filtered_symbolic_path, filtered_symbolic_path_times):
try:
time_per_screen[a] += b
except KeyError:
time_per_screen[a] = b
This will add value of a key if it already exist in dictionary else it will create a new key value pair.
Counting tasks should be best handled with Counters. Create a counter and continue appending the pairs to the counter. Finally create a dictionary from the counter which is the output you are desiring for.
from collections import Counter
for p, t in zip(filtered_symbolic_path, filtered_symbolic_path_times):
c.update({p:t})
>>> dict(c)
{'A': 3, 'C': 8, 'B': 9, 'D': 6}
You need to add
if else
to add thekeys
iteratively.Or simply