How does printf() execute its arguments with prefix and postfix unary operators?

Question

I wrote a simple code for printf in C with unary prefix operator as the following:

#include <stdio.h>
int main() {
    int i=5;
    printf("%d %d %d",++i,i,i+1);
    return 0;
}

And this is the output:

6 6 6

Now, what I have understood is that C compilers usually execute printf() arguments from right to left and so in that case i+1 should be 6 (since i is 5), i should be 5 and ++i would first become 6 and then print. Hence expected output in my opinion should be: 6 5 6

If it executes from left to right, we should get 6 6 7.