Here I come with my new C question, I have an array of char arrays and I want to reserve memory contiguously in memory to helps write into file with a single call.
ok, that's what I have:
#define PACKET_SIZE 40960
#define BUFFER_SIZE 3950
#define N_BUFFERS 4
typedef struct buffer{
int lock;
char (*rxbuf)[BUFFER_SIZE][PACKET_SIZE];
}buffer;
/* Buffer list */
buffer bufferlist[N_BUFFER];
[...]
/* I use this to init structs */
void initializeData() {
for (int i = 0; i < N_BUFFER; i++) {
bufferlist[i].lock = 0;
bufferlist[i].rxbuf = malloc(sizeof(???)); /* ??? <- I don't know what to put here */
}
}
/* After I insert data */
for (int ibuffer = 0; ibuffer < N_BUFFER; ibuffer++) {
for (int idata = 0; idata < BUFFER_SIZE; idata++) {
/* Here I want to pass char array[PACKET_SIZE] */
int bytes_received = insertData(bufferlist[ibuffer].rxbuf[idata], sizeof(bufferlist[ibuffer].rxbuf[idata]));
[...]
}
}
[...]
/* Then write with this */
fwrite(bufferlist[i].rxbuf, sizeof(????), 1, outfile);
Please can you help me with this code?
Thanks in advance
Change your definition of char array in structure
to
With this you already create char array and reserve memory, so no need to
malloc()
.You can do
fwrite()
as