Currently I try to minimize the function and get optimized parameters using GPyOpt.
import GPy
import GPyOpt
from math import log
def f(x):
x0,x1,x2,x3,x4,x5 = x[:,0],x[:,1],x[:,2],x[:,3],x[:,4],x[:,5],
f0 = 0.2 * log(x0)
f1 = 0.3 * log(x1)
f2 = 0.4 * log(x2)
f3 = 0.2 * log(x3)
f4 = 0.5 * log(x4)
f5 = 0.2 * log(x5)
return -(f0 + f1 + f2 + f3 + f4 + f5)
bounds = [
{'name': 'x0', 'type': 'discrete', 'domain': (1,1000000)},
{'name': 'x1', 'type': 'discrete', 'domain': (1,1000000)},
{'name': 'x2', 'type': 'discrete', 'domain': (1,1000000)},
{'name': 'x3', 'type': 'discrete', 'domain': (1,1000000)},
{'name': 'x4', 'type': 'discrete', 'domain': (1,1000000)},
{'name': 'x5', 'type': 'discrete', 'domain': (1,1000000)}
]
myBopt = GPyOpt.methods.BayesianOptimization(f=f, domain=bounds)
myBopt.run_optimization(max_iter=100)
print(myBopt.x_opt)
print(myBopt.fx_opt)
I want to add limiting conditions to this function. Here is an example.
x0 + x1 + x2 + x3 + x4 + x5 == 100000000
How should I modify this code?
I found a faster way.
If you need X0+X1.....Xn ==100000000 , you only give X0+X1....Xn-1 to GpyOpt.
After GpyOpt give you (X0+X1.....Xn-1), you can get
Xn = 100000000 - sum(X0+X1.....Xn-1)