How do I access the original point in periodic 2 D Triangulation in CGAL?

Question

I did the periodic triangulation of five points with the default domain.The points were (0.2,0.3), (0.5,0.1), (0.7,0.6), (0.8,0.8), (0.5,0.11). After iterating over the faces for 1 sheeted covering and printing the output, I got this result:

0.8 0.8 , 0.7 0.6 , 1.2 1.3 and so on.

I know the points 1.2 1.3 means the point 0.2 0.3 as the domain is iso_ rectangle. But I want it to print 0.2 0.3 instead of 1.2 1.3 so that I could find the delaunay neighbours of a given vertex.

Thank you

Answer 1

If you have a vertex v of the periodic triangulation t, then t.periodic_point(v) gives you a periodic point, whose first element is a point in the original domain. I guess that this point is what you are looking for. See http://doc.cgal.org/latest/Periodic_2_triangulation_2/classCGAL_1_1Periodic__2__triangulation__2.html#a217b56b0d5a8c222573f520a69a696ee and http://doc.cgal.org/latest/Periodic_2_triangulation_2/classCGAL_1_1Periodic__2__triangulation__2.html#abc48042ca1cff117f7c5201c0ffdabfa