Following is my main.qml:
Window {
id: window
visible: true
width: 800
height: 480
title: qsTr("Hello World")
ListModel {
id: _listModel
ListElement {
textData: "E1"
isEnabled: false
}
ListElement {
textData: "E2"
isEnabled: false
}
ListElement {
textData: "E3"
isEnabled: false
}
ListElement {
textData: "E4"
isEnabled: false
}
ListElement {
textData: "E5"
isEnabled: false
}
ListElement {
textData: "E6"
isEnabled: false
}
}
ListView {
id: _listview
model: _listModel
width: 100
height: parent.height
anchors.right: parent.right
delegate: Item {
width: parent.width
height: 50
anchors.right: parent.right
Component.onCompleted:
{
if (isEnabled)
visibleRecs++;
}
RowLayout {
Text {
id: itemText
text: qsTr(textData)
}
CheckBox {
height: 30
width: height
checked: isEnabled
onCheckedChanged: {
isEnabled = checked
}
}
}
}
}
ScrollView {
id: _scrollView
width: parent.width / 2
height: parent.height
clip: true
GridLayout {
id: _gridLayout
anchors.fill: parent
anchors.horizontalCenter: parent.horizontalCenter
columnSpacing: 10
rowSpacing: 10
columns: 2
Repeater {
model: _listModel
Loader {
id: _loader
sourceComponent: isEnabled ? _recComponent : null
onLoaded: {
item.text = textData
}
}
}
}
}
Component {
id: _recComponent
Rectangle {
property alias text : _txt.text
id: _rec
width: 100
height: 50
radius: 5
color: "yellow"
Text {
id: _txt
anchors.centerIn: parent
}
}
}
}
The above code creates following (when all check boxes are ticked):
When all checkboxes are ticked:
When checkbox E3 is unchecked:
I want the items to be rearranged in the gridlayout if any of the item goes invisible.
E.g. in the above case when E3 is unchecked, I want my view to be something like this:
Please let me know, if it is possible to achieve. Thanks in advance.
The problem is that you still instantiate the
Loader
, you just set thesourceComponent
tonull
. You have to make the item invisible to not use space in theGridLayout
(or put width/height to 0)