I am using Yii framework and I have got a problem with CRUD generator. I have got two tables called Users and news with the following structures:
CREATE TABLE IF NOT EXISTS `news` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`keyword` varchar(1000) COLLATE utf8_persian_ci DEFAULT NULL,
`user_id` tinyint(3) unsigned NOT NULL,
`title` varchar(100) COLLATE utf8_persian_ci DEFAULT NULL,
`body` varchar(1000) COLLATE utf8_persian_ci DEFAULT NULL,
`publishedat` date DEFAULT NULL,
`state` tinyint(1) unsigned DEFAULT NULL,
`archive` tinyint(1) unsigned DEFAULT NULL,
`last_modified` datetime DEFAULT NULL,
PRIMARY KEY (`id`),
KEY `news_FKIndex1` (`keyword`(255)),
KEY `news_FKIndex2` (`user_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_persian_ci AUTO_INCREMENT=3 ;
CREATE TABLE IF NOT EXISTS `users` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`username` varchar(20) NOT NULL,
`password` varchar(128) NOT NULL,
`create_at` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
`lastvisit_at` timestamp NULL DEFAULT NULL,
`is_disabled` tinyint(1) NOT NULL DEFAULT '1',
PRIMARY KEY (`id`),
UNIQUE KEY `username` (`username`),
KEY `status` (`is_disabled`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=7 ;
when I generate a CRUD using Gii for my news table I cannot see the fields for users table. Instead of user_id I want to see the username in the table created by CRUD generator. How can I make a change in the code to get the result as above?
First,
user_id
needs to be a foreign key field not just a key field.Second, gii will not generate the field as you require by default. For such functionality an extension such as Giix might help. However, since a relation exists you could always use
relationName.username
to display theusername
in a grid view or a list view.