I have mongo collection:
{
"_id" : 123,
"index" : "111",
"students" : [
{
"firstname" : "Mark",
"lastname" : "Smith"),
}
],
}
{
"_id" : 456,
"index" : "222",
"students" : [
{
"firstname" : "Mark",
"lastname" : "Smith"),
}
],
}
{
"_id" : 789,
"index" : "333",
"students" : [
{
"firstname" : "Neil",
"lastname" : "Smith"),
},
{
"firstname" : "Sofia",
"lastname" : "Smith"),
}
],
}
I want to get document that has index that is in the set of the given indexes, for example givenSet = ["111","333"] and has min length of students array. Result should be the first document with _id:123, because its index is in the givenSet and studentsArrayLength = 1, which is smaller than third.
I need to write custom JSON @Query for Spring Mongo Repository. I am new to Mongo and am stuck a bit with this problem.
I wrote something like this:
@Query("{'index':{$in : ?0}, length:{$size:$students}, $sort:{length:-1}, $limit:1}")
Department getByMinStudentsSize(Set<String> indexes);
And got error: error message '$size needs a number'
Should I just use .count() or something like that?
you should use the aggregation framework for this type of query.
filter the result based on your condition.
add a new field and assign the array size to it.
sort based on the new field.
limit the result.
the solution should look something like this:
working example: https://mongoplayground.net/p/ih4KqGg25i6