i've a problem to understand this snippet of code
output=lsqnonlin(@(argn) fun(arg1,arg2,argn),X0);
My idea is that lsqnonlin will call the argn->fun function recursively,but i'm not sure. is it right?
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It is impossible to say what
lsqnonlinwill do without the functions' code. However, there is nothing inherently recursive in the function call in your question.The 1st argument to
lsqnonlinis a function handle, and in the function call in your question, you pass an anonymous function handle:Which is a function with one argument to be used by the function,
argn, and two parameters (are pre-set arguments),arg1andarg2.lsqnonlinuses the function handle you pass it in order to calculate the function value in a specific point or vector of points.You can read more about anonymous function handle here: http://www.mathworks.com/help/techdoc/matlab_prog/f4-70115.html#f4-70133