FLWOR in Sql server count number of hits

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I am using SQL Server 2008 R2. My problem is that I want to count number of hits that i receive from XQuery query using FLWOR. For each hit, I want a consecutive number, like: 0,1,2,3,4...

My query:

select @xml.query('for $s at $count in /Root/Persons/Person
return <Person ID="{$count}">{$s}</Person>')

The only problem here is this is not supported in SQL Server and I receive an error:

Msg 9335, Level 16, State 1, Line 16
XQuery [query()]: The XQuery syntax 'at' is not supported.

I've also tried with let keyword and define new variable but I don't know how to increase value of that variable with each iteration?

Thanks for all the answers, Frenky

2

There are 2 answers

3
Jens Erat On BEST ANSWER

XQuery is a declarative language, you cannot use let to increment a counter.

A rather hackish workaround to the missing at feature would be to count the preceding sibling <person/> tags:

for $person in /Root/Persons/Person
let $count := count($person/preceding-sibling::Person) + 1
return <Person ID="{$count}">{$person}</Person>

Be aware that this code will have O(n^2) runtime if not optimized by the execution engine (which it will probably not do) because of the repeated preceding sibling scans.


Edit: As stated in the comments, MS SQL doesn't even support the preceding-sibling axis. They do support the << node order comparison operator, though. This query should be fully supported:

for $person in /Root/Persons/Person
let $count := count($person/parent::Persons/Person[. << $person]) + 1
return <Person ID="{$count}">{$person}</Person>

By the way, you possibly only want to paste the person's name, so better use

(: snip :)
return <Person ID="{$count}">{data($person)}</Person>
1
adamretter On

Another possible formulation that may arguably be easier to read if you are not so familiar with XQuery:

for $i in (1 to count(/Root/Persons/Person))
let $person := /Root/Persons/Person[$i]
return
    <Person ID="{$i}">{$person}</Person>

Also if SQL Server does/ever support(s) XQuery 3.0, then you could do the following which is rather nice:

/Root/Persons/Person ! <Person ID="{position()}">{data(.)}</Person>