Does Java has a default copy constructor as C++? If it has one - does it remain usable if I declare another constructor (not a copy constructor) explicitly?
Does Java have a default copy constructor (like in C++)?
11.1k views Asked by thedarkside ofthemoon AtThere are 7 answers
No, it doesn't have a default copy constructor. A default constructor.
You don't have to provide any constructors for your class, but you must be careful when doing this. The compiler automatically provides a no-argument, default constructor for any class without constructors. This default constructor will call the no-argument constructor of the superclass. In this situation, the compiler will complain if the superclass doesn't have a no-argument constructor so you must verify that it does. If your class has no explicit superclass, then it has an implicit superclass of Object, which does have a no-argument constructor.
Usually I provide a one like,
public class CopyConEx {
/**
* Regular constructor.
*/
public CopyConEx(type field1, type field2) {
this.field1 = field1;
this.field2 = field2;
}
/**
* Copy constructor.
*/
public CopyConEx(CopyConEx aCopyConEx) {
this(aCopyConEx.getField1(), aCopyConEx.getField2());
}
Java support cloning but not using copy constructor. Please find below url on Java cloning.
http://adtmag.com/articles/2000/01/18/effective-javaeffective-cloning.aspx
In Java the provision of an automatic copy constructor would be pointless.
Java doesn't need one since you can only have references to objects. (In C++ you can pass objects round by value so the grammar needs to allow for an automatic object copy).
If you need to take deep copies of object in Java, then implement Cloneable
.
Java does not have bulit-in copy constructors.
But you can write your own such constructors. See an example below: