I do not think there is a hazard, but wanted to confirm.
I know that if there was a load word then I should assume a hazard, but is it the same for a store word?
sw $t4,8($t0)
add $t3,$t4,$t0
I do not think there is a hazard, but wanted to confirm.
I know that if there was a load word then I should assume a hazard, but is it the same for a store word?
sw $t4,8($t0)
add $t3,$t4,$t0
No registers are affected in store word .You are just taking the value from a register and storing it in a memory location .Hence no hazard