Do store instructions create a hazard the same way loads do?

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I do not think there is a hazard, but wanted to confirm.

I know that if there was a load word then I should assume a hazard, but is it the same for a store word?

sw $t4,8($t0)
add $t3,$t4,$t0
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Arunachalam Muthupalaniappan On

No registers are affected in store word .You are just taking the value from a register and storing it in a memory location .Hence no hazard