I am trying to display the content of a file, split by a delimiter character. More exactly, starting from this topic, I am trying to display the result as:
bbb
aaa
qqq
ccc
but the data source to be taken from a file.
Until now, I tried:
DECLARE
l_bfile bfile;
BEGIN
l_bfile := bfilename(my_dir, my_file);
dbms_lob.fileopen(l_bfile);
FOR i IN
(SELECT TRIM(regexp_substr(TO_CHAR(l_bfile),'[^;]+',1,level) ) AS q
FROM dual
CONNECT BY regexp_substr(TO_CHAR(l_bfile),'[^;]+',1,level) IS NOT NULL
ORDER BY level
)
LOOP
dbms_output.put_line(i.q);
END LOOP;
EXCEPTION
WHEN No_Data_Found THEN
NULL;
END;
As result, I got
PL/SQL: ORA-00932: inconsistent datatypes: expected NUMBER got FILE
Can anyone give me a hint, please?
Have to write this as a new answer since this is too big for a comment to @SmartDumb:
Be advised the regex of the form
'[^;]+'
(commonly used for parsing delimited lists) fails when NULL elements are found in the list. Please see this post for more information: https://stackoverflow.com/a/31464699/2543416Instead please use this form of the call to regexp_substr (note I removed the second element):
It may or may not be important in this example, it depends on if the order of the element in the string has importance to you or if you need to preserve the NULL. i.e. if you need to know the second element is NULL then this will work.
P.S. Do a search for external tables and see if that is a solution you could use. That would let you query a file as if it were a table.