# Determining Square Root Using Newton's Method

This is a homework assignment, to estimate the square root of a number input by the user, using Newton's method, which should return a result of < .0001. When I run the code and enter a number, nothing happens after that. In debug mode, the 'value' increases, which is the opposite of what I want it to do. Thanks in advance.

``````import java.text.DecimalFormat;
import java.util.Scanner;

public class Newton {

public static void main(String[] args)
{
// declare a Scanner class object
Scanner sc = new Scanner(System.in);
// declare a DecimalFormat class object
DecimalFormat fourDecimal =  new DecimalFormat("0.0000");

float Number = 0;

System.out.println("Program: find square roots by Newton's Method");

Number = sc.nextFloat();

System.out.println("The square root of " + Number + " is " + fourDecimal.format(Compute(Number)));
}

public static float Compute(float Number)
{
// define variable sqrRoot to hold the approximate square root
float sqrRoot = 0;
// define temporary variable temp to hold prior value of iteration
float temp = 0;
// divide variable num by 2 to start the iterative process
// and assign the quotient to temp
temp = Number/2;
// open a while() loop that continues as long as num >= 0.0
while (Number >= 0.0)
{
// construct the main iterative statement
sqrRoot = temp - (temp * temp - Number) / (2 * temp);
// open an if block to check if the absolute value of the difference of
// variables temp and sqrRoot is below a small sentinel value such as 0.0001
// if this condition is true then break the loop
float value;
value = Math.abs(temp - sqrRoot);
if (value < .0001)
// return sqrRoot as the answer
Number = sqrRoot;
// if this condition is not true then assign sqrRoot to temp
else temp = sqrRoot;

// close the while() loop
}
return Number;
}
}
``````