Define a constructor parameter for a synthetic class in a Scala Compiler Plugin?

Question

I'm trying to generate a class in a Scala compiler Plugin. I have a trait Test, and need a class TestWrapper, approximately like this:

class TestWrapper(wrapped: Test) extends Test { ... }

I define the constructor parameter like this:

val pName = newTermName("wrapped")
val paramSym = myNewClass.newValueParameter(owner.pos.focus, pName)
paramSym.setInfo(wrapped.tpe).setFlag(SYNTHETIC)
val param = ValDef(paramSym)

and later the ClassDef:

ClassDef(myNewClass, NoMods, List(List(param)), List(Nil),
        members, owner.pos)

which receives the parameter. Currently, what I get is:

// Scala source: Test.scala
[[syntax trees at end of generatewrappers]]
package test {
  <synthetic> class TestWrapper extends Object with test.Test {
    <synthetic> val wrapped: test.Test = _;
    def this(wrapped: test.Test): test.TestWrapper = {
      TestWrapper.super.this();
      ()
    };
    <synthetic> def m3: Int = TestWrapper.this.wrapped.m3;
  };

The compiler seems to be automatically generating a field with the same name as the parameter. What I don't see is the assignment from the parameter to the field, but I had assumed it was "implicit". I can than instantiate this TestWrapper with a concrete instance of Test, but calling m3 causes an Exception:

java.lang.NoSuchFieldError: wrapped
    at test.TestWrapper.m3(Test.scala:1)
    ...

"wrapped" should in fact be 3 different things:

1) A constructor parameter
2) An class instance field
3) A getter for the class instance field

The output of the compiler shows after all that there is a field:

<synthetic> val wrapped: test.Test = _;

and that it is defined, because of the "= _", as opposed to undefined, when there is no "= ..."

So, what am I missing?

Answer 1

Got it. I needed to add the following line:

myNewClass.info.decls.enter(paramSym)

Duh!