Decimal float number to Hexadecimal in Python

Question

I am trying to convert a floating point number from decimal to hexadecimal. But I am not getting in the format I want. For example, if the decimal number is 54.75, I want the hexadecimal in the format 36.C0 However, I am not able to convert it to this format.

float.hex(54.75)

gives 0x1.b600000000000p+5

Python built-in function hex() also doesn't support float numbers.

Answer 1

As stated in the comments, you can split the number into various parts and then combine the converted results. For example:

import math
import re


def get_hex(n):
    assert not math.isinf(n)
    assert not math.isnan(n)

    for sign, a, b in re.findall(r"(-?)(\d+)\.?(\d*)", str(n)):
        if b:
            return f"{sign}{int(a):X}.{int(256 * float('0.' + b)):>02X}"
        else:
            return f"{sign}{int(a):X}"


print(get_hex(54.05))
print(get_hex(54.50))
print(get_hex(54.75))
print(get_hex(15))
print(get_hex(-15))
print(get_hex(-15.21))
print(get_hex(100_000_000_000.15))

Prints:

36.0C
36.80
36.C0
F
-F
-F.35
174876E800.26