Create Class dynamically at runtime

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I have a method like this: (this is a generic method, and DYNAMIC_CLASS_TYPE will be changed in situation to other situation)

Dim res = f.MyMethod(Of DYNAMIC_CLASS_TYPE)("select Id, Name from myTable")

I want to create a dynamic class, based on my query's columns and then pass the class instead of DYNAMIC_CLASS_TYPE.

How can I do this?

4

There are 4 answers

1
Vahid Farahmandian On BEST ANSWER

I finally succeeded in doing it. My Code is as:

 Public Shared Function CreateClass(ByVal className As String, ByVal properties As Dictionary(Of String, Type)) As Type

    Dim myDomain As AppDomain = AppDomain.CurrentDomain
    Dim myAsmName As New AssemblyName("MyAssembly")
    Dim myAssembly As AssemblyBuilder = myDomain.DefineDynamicAssembly(myAsmName, AssemblyBuilderAccess.Run)

    Dim myModule As ModuleBuilder = myAssembly.DefineDynamicModule("MyModule")

    Dim myType As TypeBuilder = myModule.DefineType(className, TypeAttributes.Public)

    myType.DefineDefaultConstructor(MethodAttributes.Public)

    For Each o In properties

        Dim prop As PropertyBuilder = myType.DefineProperty(o.Key, PropertyAttributes.HasDefault, o.Value, Nothing)

        Dim field As FieldBuilder = myType.DefineField("_" + o.Key, o.Value, FieldAttributes.[Private])

        Dim getter As MethodBuilder = myType.DefineMethod("get_" + o.Key, MethodAttributes.[Public] Or MethodAttributes.SpecialName Or MethodAttributes.HideBySig, o.Value, Type.EmptyTypes)
        Dim getterIL As ILGenerator = getter.GetILGenerator()
        getterIL.Emit(OpCodes.Ldarg_0)
        getterIL.Emit(OpCodes.Ldfld, field)
        getterIL.Emit(OpCodes.Ret)

        Dim setter As MethodBuilder = myType.DefineMethod("set_" + o.Key, MethodAttributes.[Public] Or MethodAttributes.SpecialName Or MethodAttributes.HideBySig, Nothing, New Type() {o.Value})
        Dim setterIL As ILGenerator = setter.GetILGenerator()
        setterIL.Emit(OpCodes.Ldarg_0)
        setterIL.Emit(OpCodes.Ldarg_1)
        setterIL.Emit(OpCodes.Stfld, field)
        setterIL.Emit(OpCodes.Ret)

        prop.SetGetMethod(getter)
        prop.SetSetMethod(setter)

    Next

    Return myType.CreateType()

End Function

The return value of the function is a Type of my Custom Class.

3
Steve On

A much simpler way is to use the System.Activator:

Activator.CreateInstance(YourType, ParramArrayOfYourVariablesForNEW)

So say I have a class (Test) that takes a single string in the initialization

Public Class Test
    Public Sub New(byval MyString as string)
...

You could create a new instance like this:

Activator.CreateInstance(gettype(Test),"My String")
0
Jacek_D73 On

There seems to be a bug. I think this line:

Dim field As FieldBuilder = myType.DefineField("_" + o.Key, GetType(Integer), FieldAttributes.[Private])

should look like this:

Dim field As FieldBuilder = myType.DefineField("_" + o.Key, o.Value, FieldAttributes.[Private])

Regards.

0
Lunadix On

This line:

Dim field As FieldBuilder = myType.DefineField("_" + o.Key, GetType(Integer), FieldAttributes.[Private])

must to be replaced with this:

Dim field As FieldBuilder = myType.DefineField("_" + o.Key, o.Value, FieldAttributes.[Private])