We have a program that will take a file as input, and then count the lines in that file, but without counting the empty lines.
There is already a post in Stack Overflow with this question, but the answer to that doesn't cover me.
Let's take a simple example.
File:
I am John\n
I am 22 years old\n
I live in England\n
If the last '\n' didn't exist, then the counting would be easy. We actually already had a function that did this here:
/* Reads a file and returns the number of lines in this file. */
uint32_t countLines(FILE *file) {
uint32_t lines = 0;
int32_t c;
while (EOF != (c = fgetc(file))) {
if (c == '\n') {
++lines;
}
}
/* Reset the file pointer to the start of the file */
rewind(file);
return lines;
}
This function, when taking as input the file above, counted 4 lines. But I only want 3 lines.
I tried to fix this in many ways.
First I tried by doing fgets
in every line and comparing that line with the string "\0". If a line was just "\0" with nothing else, then I thought that would solve the problem.
I also tried some other solutions but I can't really find any.
What I basically want is to check the last character in the file (excluding '\0') and checking if it is '\n'. If it is, then subtract 1 from the number of lines it previously counted (with the original function). I don't really know how to do this though. Are there any other easier ways to do this?
I would appreciate any type of help. Thanks.
You can actually very efficiently amend this issue by keeping track of just the last character as well.
This works because empty lines have the property that the previous character must have been an
\n
.