Commandline subtitution on ksh is not being assigned to varibale

Question

var2=$(echo "{$1}" | grep 'Objects that are still invalid after the validation:' | cut -d : -f2 | sed 's/ //g')
echo $var2

the above commandline substitution is not working ksh, the variable is blank each time, have tried below command too

var2="$(echo "{$1}" | grep 'Objects that are still invalid after the validation:' | cut -d : -f2 | sed 's/ //g')"
var2=`echo "{$1}" | grep 'Objects that are still invalid after the validation:' | cut -d : -f2 | sed 's/ //g'`
var2=`echo "$1" | grep 'Objects that are still invalid after the validation:' | cut -d : -f2 | sed 's/ //g'`

please hep me resolve the issue. The command is being used on remote server after ssh. The commands are working on the remote server if executed directly on the server without ssh.

Answer 1

What is supposed to be in $1 ? First issue is that it ought to be written as either $1 or as ${1}. Writing it as {$1} is plain wrong.

Then there is the useless use of grep and cut. The following works:

var2=$(echo ${1} | sed -ne 's/ //g' -e 's/Objectsthatarestillinvalidafterthevalidation:\(.*\)/\1/p')