Can't find stderr print in python smtpd

91 views Asked by At

I am using smtpd and its catching ValueError exceptions I raise in process_message and printing a description to stderr instead of raising the error. What it prints out is the string I construct the ValueError with.

So if I do this in process_message:

raise ValueError("550, This is the error")

I see

550, This is the error

on the console. I cannot for the life of me find what code is causing the print. Is there anyway to override stderr to show a stacktrace each time something is printed or otherwise locate what lines of code are printing out these lines?

1

There are 1 answers

0
Aaron Digulla On BEST ANSWER

You can replace one the standard output streams with something that traces invocations of write():

import sys
import traceback

class FileTracer(object):
    def __init__(self, out):
        self.out = out

    def write(self, data):
        traceback.print_stack(None, None, sys.__stderr__)
        self.out.write(data)

    def flush(self):
        self.out.flush()

    def close(self):
        self.out.close()

sys.stderr = FileTracer(sys.stderr)

sys.stderr.write("trigger\n")
sys.stderr.flush()

Note that I'm using __stderr__ to avoid loops.