Can pailler cryptosystem encrypt and decrypt negative big integers?

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I use paillier cryptosystem to encrypt and decrypt random data which at first are in the form of byte arrays and then i transform them to big integers and if the byte array become a negative big integer the decrypted number and the input number are different (basically it doesn't work with negative big integers). Is there a way to make this work without checking the input if it will become positive or negative ?

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Maarten Bodewes On BEST ANSWER

No, you cannot use negative numbers as everything is computed modulo n.

Yes, you can use any array, as long as the value, when converted to a number, is a number smaller than n.

For this you can use new BigInteger(1, plaintext) which will always result in a positive number. The first parameter is the sign.

You may need an encoding for specific structures, e.g. with zero bit values for the most significant bits (message-> encode-> convert to number -> Paillier encryption -> encode ciphertext and decode ciphertext -> Paillier decryption -> decode -> message).

See I2OSP and OS2IP for an example on how to encode / decode data to numbers.

0
sefiks On

Paillier cryptosystem is defined over modulo n for plaintexts and n^2 for ciphertexts. So, if you even encrypt a negative number, it is going to have a positive equivalent for modulo n. This can be proven in python as:

# pip install lightphe
from lightphe import LightPHE
 
# build a cryptosystem
cs = LightPHE(algorithm_name = 'Paillier')
modulo = cs.cs.plaintext_modulo
 
# define plaintexts
m1 = -10
 
# calculate ciphertexts
c1 = cs.encrypt(m1)
 
# performing homomorphic addition on ciphertexts
assert cs.decrypt(c1) == m1 % modulo