**Updated. Sorry to those whose answers no longer make sense.
So I figured out that no matter what I put on the line after Data_pair_node, after it executes, thats when the thing is reset! WTH? :
int insert(Table *t, const char *key, const char *val){
int dest_bucket_index;
Table *table = t;
Hash_bucket *dest_bucket = NULL;
Data_pair_node *current = NULL, *prev = NULL, *new_item = NULL;
printf("gonna be zero now");
Lo and behold:
$23 = (Hash_bucket *) 0x834010
(gdb) step
109 printf("gonna be zero now");
(gdb) print table->buckets
$24 = (Hash_bucket *) 0x0
Thanks Aymon Fournier
You're using an integer divide (both list_count and table->bucket_ct are ints), so your result will be truncated and you'll get a return value of 0 if the average bucket list length is less than 1.0 -- if you have more buckets in the hash table than entries.
Since you want a double answer, it makes more sense to use a double divide:
edit
It's tough to tell what's going on as you never print out the value of
table
or show the code that callsinsert
(which is where it gets its value). But a couple of things might be going on.table
is a local var so the compiler might put it in a register and reuse that register for something else oncetable
is dead (after the last use in the code), in which case printingtable
at that point (or anything depending on it) with gdb might print anything.if
table
is a dangling pointer into the stack (it comes from another function that returned the address of a local variable), it might well be pointing at memory used for some other local vars, in which case assigning to those local vars will change the value oftable->buckets