I am developing a blackberry app. I want to open an screen from the home screen when user will press one button and hold it for 2 seconds.
Any way?
Thanks.
I am developing a blackberry app. I want to open an screen from the home screen when user will press one button and hold it for 2 seconds.
Any way?
Thanks.
Here is the code for your question. I have make use of this BlackBerry LongClickListener implementation link which contains good explanation too.
public class HoldButtonScreen extends MainScreen implements FieldChangeListener {
ButtonField _btnHold;
Timer _timer;
public HoldButtonScreen() {
_btnHold = new ButtonField("Hold 2 sec to get popup")
{
protected boolean navigationClick(int status, int time) {
final Field _btnHold= this;
_timer = new Timer();
System.out.println("hi there");
UiApplication.getUiApplication().invokeLater(new Runnable() {
public void run() {
try{
_timer.schedule(new TimerTask() {
public void run() {
fieldChanged(_btnHold, 0);
}}, 2000);
}catch(Exception e){
e.printStackTrace();
}
}
});
return true;
}
protected boolean navigationUnclick(int status, int time) {
System.out.println("hi unclick");
add(new LabelField("You have't hold button for 2 second."));
_timer.cancel();
return true;
}
};
_btnHold.setChangeListener(this);
add(_btnHold);
}
public void fieldChanged(Field field, int context) {
UiApplication.getUiApplication().invokeLater(new Runnable() {
public void run() {
PopupScreen _popUpScreen = new PopupScreen(new VerticalFieldManager()){
public boolean onClose() {
close();
return true;
}
};
_popUpScreen.add(new LabelField("Hello , i am pop up after 2 second."));
UiApplication.getUiApplication().pushScreen(_popUpScreen);
}
});
}
}
Try this this will run successfully. Just change the Screen in PushScreen.