Here's a simple program that registers two trap
handlers and then displays them with trap -p
. Then it does the same thing, but in a child background process.
Why does the background process ignore the SIGINT
trap?
#!/bin/bash
echo "Traps on startup:"
trap -p
echo ""
trap 'echo "Received INT"' INT
trap 'echo "Received TERM"' TERM
echo "Traps set on parent:"
trap -p
echo ""
(
echo "Child traps on startup:"
trap -p
echo ""
trap 'echo "Child received INT"' INT
trap 'echo "Child received TERM"' TERM
echo "Traps set on child:"
trap -p
echo ""
) &
child_pid=$!
wait $child_pid
Output:
$ ./show-traps.sh
Traps on startup:
Traps set on parent:
trap -- 'echo "Received INT"' SIGINT
trap -- 'echo "Received TERM"' SIGTERM
Child traps on startup:
Traps set on child:
trap -- 'echo "Child received TERM"' SIGTERM
SIGINT
andSIGQUIT
are ignored in backgrounded processes (unless they're backgrounded withset -m
on). It's a (weird) POSIX requirement (see 2. Shell Command Language or my SO question Why do shells ignore SIGINT and SIGQUIT in backgrounded processes? for more details).Additionally, POSIX requires that:
However, even if you set the
INT
handler in the subshell again after it was reset, the subshell won't be able to receive it because it's ignored (you can try it or you can inspect the signal ignore mask usingps
, for example).