How do you print out the literal string of special character in bash? I always get the expand \t
character. For example the code below:
value="0.1"
ln=5
thestring=$(printf $'%si \
var1=$(dpkg-query -s "$1" | grep \'Package:\' | sed \'s/^.*: //\') \
var2=$(grep -m 1 "^$1$(printf \'%s\').*$(printf \'%s\')$value" file.txt) \
' "$ln" "\\t" "\\t")
sed "$thestring" -i somefile.txt
For var2
the \t
character is expanded, I expected an output that looks like:
var2=$(grep -m 1 "^$1$(printf '\t').*$(printf '\t')$value" file.txt)
Any idea? Thanks!