Android specific words speech recognition

Question

I am trying to have the app recognize certain words said by the user using the code below, but for some reason it isn't working at all. Please review this and tell me what is wrong with it. Thank you

The app is simply suppose to display a toast message if the words "orange" or "apple" is said but nothing happens when using the code below.

//button onclick to trigger RecognizerIntent

public void OnClick_Speed_Detector(View v)
{
    Intent i = new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH);
    i.putExtra(RecognizerIntent.EXTRA_LANGUAGE, RecognizerIntent.LANGUAGE_MODEL_FREE_FORM);
    i.putExtra(RecognizerIntent.EXTRA_PROMPT, "speak up");
    startActivityForResult(i, 1);

}

protected void onActivityResult(int requestCode, int resultCode, Intent data)
{
    if(requestCode == 1 && resultCode == RESULT_OK)
    {
        ArrayList<String> result = 
                data.getStringArrayListExtra(RecognizerIntent.EXTRA_RESULTS);

                if(((result).equals("orange")))
                {
                  Toast.makeText(getApplicationContext(), "orange", Toast.LENGTH_LONG).show();

                }   
                else
                    if (((result).equals("apple")))
                { 
                  Toast.makeText(getApplicationContext(), "apple", Toast.LENGTH_LONG).show();   
                }

    }
}

Answer 1

Your issue is that you are testing if an ArrayList == a String, when it can't possibly (an ArrayList of type String contains multiple strings)

Instead of:

if ((result).equals("orange")) {}

Try:

if ((result).contains("orange")) {}

This code will look through every index of the ArrayList and determine if any of the indexes of it equal "orange". If any do then it will return

true

...and it will execute the if statement! Hope this helps!

Answer 2

String word1= "orange";
String encoded1 = Soundex.US_ENGLISH.encode(name1); 
String word2= user's spoken word;
String encoded2 = Soundex.US_ENGLISH.encode(name2); 


encoded1.equals(encoded2)

// OR for loose matching...
encoded1.contains(encoded2) || encoded2.contains(encoded1)

This matches similar sounding words

for better matching you can use Metaphone3 algorithm. You just need to get the code snippet from internet or write yourself (most probably you won't). By using metaphone3 you will get below matchings 'by' == 'bye' "john's" == 'john' '(./cow' == 'cow' 'y' == 'why'