The problem found in programming pearls column 8 is as follows:
Given the real vector x[n], compute the maximum sum found in any contiguous subvector.
The final solution provided is of O(n) complexity which is as follows:
std::vector<int> x;
int max_so_far = 0;
int max_here = 0;
for (std::size_t i = 0; i < x.size(); ++i)
{
max_here = std::max(max_here + x[i], 0);
max_so_far = std::max(max_so_far, max_here);
}
I would like to know how does one go about modifing the above algorithm to provide the minimum sum.
You only need to invert the sign of each element in
x
and then run the algorithm: