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How do I add a class inside the XML root, in an existing XML file?

score 327 · Answer 1 · 2020-12-02 13:58:31

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How do I add a class inside the XML root, in an existing XML file?

327 views Asked by Henry Boo At 02 December 2020 at 13:58

score 226 · Answer 2 · 2021-05-07 08:30:03

XmlElement shows up as lowercase in SOAP

226 views Asked by A.J At 07 May 2021 at 08:30

score 15829 · Answer 3 · 2009-12-22 11:43:02

XmlSerializer Deserializing Array/List of Multiple Objects at Root

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score 267 · Answer 4 · 2018-10-01 13:14:36

Replace ArrayOf* Root Element using API Controller in Visual Studio C#

267 views Asked by Adam At 01 October 2018 at 13:14

score 60 · Answer 5 · 2021-05-31 13:40:31

How to add a root to an XML file?

60 views Asked by user3474218 At 31 May 2021 at 13:40

score 209 · Answer 6 · 2020-04-02 12:06:53

One POJO but the different XmlRootElement name

209 views Asked by DaviesTobi alex At 02 April 2020 at 12:06

score 991 · Answer 7 · 2015-05-21 00:50:36

XmlRoot attribute serialization to a file

991 views Asked by Romonov At 21 May 2015 at 00:50

score 966 · Answer 8 · 2010-03-10 13:28:57

Rename serializable class

966 views Asked by Andreas At 10 March 2010 at 13:28

score 41128 · Answer 9 · 2013-01-14 17:18:23

Get attribute names and values from ElementTree

41.1k views Asked by Igal At 14 January 2013 at 17:18

score 575 · Answer 10 · 2018-12-10 09:09:48

JAXB dynamic XML root class name

575 views Asked by Matija Župančić At 10 December 2018 at 09:09

TechQA.

List Question

How do I add a class inside the XML root, in an existing XML file?

XmlElement shows up as lowercase in SOAP

XmlSerializer Deserializing Array/List of Multiple Objects at Root

Replace ArrayOf* Root Element using API Controller in Visual Studio C#

How to add a root to an XML file?

One POJO but the different XmlRootElement name

XmlRoot attribute serialization to a file

Rename serializable class

Get attribute names and values from ElementTree

JAXB dynamic XML root class name

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