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Question

How do I add a class inside the XML root, in an existing XML file?

score 316 · Answer 1 · 2024-09-21 05:50:59

How do I add a class inside the XML root, in an existing XML file?

score 211 · Answer 2 · 2024-09-21 06:14:31

XmlElement shows up as lowercase in SOAP

211 views Asked by A.J At 21 September 2024 at 06:14

score 15818 · Answer 3 · 2024-09-21 02:34:01

XmlSerializer Deserializing Array/List of Multiple Objects at Root

score 255 · Answer 4 · 2024-09-21 04:48:34

Replace ArrayOf* Root Element using API Controller in Visual Studio C#

score 48 · Answer 5 · 2024-09-21 07:40:00

How to add a root to an XML file?

48 views Asked by user3474218 At 21 September 2024 at 07:40

score 197 · Answer 6 · 2024-09-21 02:03:25

One POJO but the different XmlRootElement name

197 views Asked by DaviesTobi alex At 21 September 2024 at 02:03

score 978 · Answer 7 · 2024-09-21 11:54:24

XmlRoot attribute serialization to a file

978 views Asked by Romonov At 21 September 2024 at 11:54

score 952 · Answer 8 · 2024-09-21 13:53:46

Rename serializable class

952 views Asked by Andreas At 21 September 2024 at 13:53

score 41118 · Answer 9 · 2024-09-21 11:52:21

Get attribute names and values from ElementTree

score 562 · Answer 10 · 2024-09-21 02:36:33

JAXB dynamic XML root class name

562 views Asked by Matija Župančić At 21 September 2024 at 02:36

TechQA.

List Question

How do I add a class inside the XML root, in an existing XML file?

XmlElement shows up as lowercase in SOAP

XmlSerializer Deserializing Array/List of Multiple Objects at Root

Replace ArrayOf* Root Element using API Controller in Visual Studio C#

How to add a root to an XML file?

One POJO but the different XmlRootElement name

XmlRoot attribute serialization to a file

Rename serializable class

Get attribute names and values from ElementTree

JAXB dynamic XML root class name

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