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why std::result_of can't accept function type?

score 72 · Answer 1 · 2023-01-24T05:43:46.063000

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why std::result_of can't accept function type?

72 views Asked by Kevin eyeson At 24 January 2023 at 05:43

score 332 · Answer 2 · 2023-01-21T13:22:22.463000

How C++ 11 std::result_of or C++ 17 invoke_result works

332 views Asked by edKotinsky At 21 January 2023 at 13:22

score 77 · Answer 3 · 2020-01-01T14:40:49.347000

std::result_of syntax kerfuffle

77 views Asked by einpoklum At 01 January 2020 at 14:40

score 76 · Answer 4 · 2019-12-02T09:01:14.303000

Why does operator () with type argument can be applied to type in the context of result_of?

76 views Asked by P. Dmitry At 02 December 2019 at 09:01

score 85 · Answer 5 · 2019-10-14T15:34:36.970000

Variadic template for decuction for member parameter

85 views Asked by Iacopo Breschi At 14 October 2019 at 15:34

score 781 · Answer 6 · 2019-03-04T13:51:08.867000

Can I get the Return Type of a Function From a Signature?

781 views Asked by Jonathan Mee At 04 March 2019 at 13:51

score 1650 · Answer 7 · 2019-01-07T11:10:37.653000

Use invoke_result with void argument type?

1.6k views Asked by haelix At 07 January 2019 at 11:10

score 3733 · Answer 8 · 2018-11-08T17:53:28.403000

error: `type` in `class std::result_of` does not name a type

3.7k views Asked by hutorny At 08 November 2018 at 17:53

score 270 · Answer 9 · 2018-09-10T08:14:34.703000

c++ how to define a std::result_of<F(R)> that can handle R is void

270 views Asked by D.pz At 10 September 2018 at 08:14

score 745 · Answer 10 · 2018-06-13T04:43:43.783000

C++11: std::result_of<> template argument vs std::function<>

745 views Asked by Dejavu At 13 June 2018 at 04:43

score 2209 · Answer 11 · 2018-06-06T09:00:57.450000

Deduce return type of member function

2.2k views Asked by KorbenDose At 06 June 2018 at 09:00

score 173 · Answer 12 · 2018-06-04T15:17:58.167000

How can I use std::result_of to return the function type instead of void

173 views Asked by Jon At 04 June 2018 at 15:17

score 103 · Answer 13 · 2018-04-27T18:20:38.600000

Using std::result_of<> for member method of member type

103 views Asked by Niklas R At 27 April 2018 at 18:20

score 724 · Answer 14 · 2018-01-11T19:21:11.233000

get resulting type of std::bind

724 views Asked by user3617992 At 11 January 2018 at 19:21

score 9046 · Answer 15 · 2017-12-18T19:43:46.593000

Correct way of using invoke_result?

9k views Asked by Vincent At 18 December 2017 at 19:43

score 9539 · Answer 16 · 2017-09-03T08:48:02.027000

What is the reason for `std::result_of` deprecated in C++17?

9.5k views Asked by msc At 03 September 2017 at 08:48

score 183 · Answer 17 · 2017-03-02T08:03:19.840000

gcc 6.1 std::result_of compilation error

183 views Asked by Recker At 02 March 2017 at 08:03

score 492 · Answer 18 · 2017-03-01T12:23:38.327000

Using std::result_of with an overloaded method

492 views Asked by Class Skeleton At 01 March 2017 at 12:23

score 3800 · Answer 19 · 2017-02-16T09:27:03.960000

no type named "type" in "std::result_of" ; get return type from overloading functions

3.8k views Asked by javaLover At 16 February 2017 at 09:27

score 500 · Answer 20 · 2017-02-08T12:58:16.753000

result_of does not define type for mem_fn

500 views Asked by phimuemue At 08 February 2017 at 12:58

TechQA.

List Question

why std::result_of can't accept function type?

How C++ 11 std::result_of or C++ 17 invoke_result works

std::result_of syntax kerfuffle

Why does operator () with type argument can be applied to type in the context of result_of?

Variadic template for decuction for member parameter

Can I get the Return Type of a Function From a Signature?

Use invoke_result with void argument type?

error: `type` in `class std::result_of` does not name a type

c++ how to define a std::result_of<F(R)> that can handle R is void

C++11: std::result_of<> template argument vs std::function<>

Deduce return type of member function

How can I use std::result_of to return the function type instead of void

Using std::result_of<> for member method of member type

get resulting type of std::bind

Correct way of using invoke_result?

What is the reason for `std::result_of` deprecated in C++17?

gcc 6.1 std::result_of compilation error

Using std::result_of with an overloaded method

no type named "type" in "std::result_of" ; get return type from overloading functions

result_of does not define type for mem_fn

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