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Calling Protected Function From Derived Friend Function

score 201 · Answer 1 · 2015-06-10 21:57:52

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Calling Protected Function From Derived Friend Function

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score 127 · Answer 2 · 2015-06-11 08:18:12

Trying to befriend a function of Derived in Base - Why doesn't it work?

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score 113 · Answer 3 · 2015-06-21 02:50:45

C++ Can friends classes access all of the members of its base class?

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score 138 · Answer 4 · 2015-06-23 13:44:02

I don't understand how the template function gets to be a friend of the class A::X::Y in the example in [namespace.memdef]/3 in C++14

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Friend lookup exception from template-id?

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score 118 · Answer 6 · 2015-06-23 06:10:29

Issue with declare friend template class

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score 107 · Answer 7 · 2015-06-25 11:40:53

Lambda expressions (C++0x) not working in C++/CLI?

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score 850 · Answer 8 · 2016-12-16 23:18:15

friend declaration specifying a default argument must be a definition error

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score 243 · Answer 9 · 2016-12-18 07:40:36

C++ friend class of the same name in different levels of a nested namespace

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score 1003 · Answer 10 · 2016-12-19 01:36:56

C++ friend a function in a separate namespace

1k views Asked by AudioBubble At 19 December 2016 at 01:36

TechQA.

List Question

Calling Protected Function From Derived Friend Function

Trying to befriend a function of Derived in Base - Why doesn't it work?

C++ Can friends classes access all of the members of its base class?

I don't understand how the template function gets to be a friend of the class A::X::Y in the example in [namespace.memdef]/3 in C++14

Friend lookup exception from template-id?

Issue with declare friend template class

Lambda expressions (C++0x) not working in C++/CLI?

friend declaration specifying a default argument must be a definition error

C++ friend class of the same name in different levels of a nested namespace

C++ friend a function in a separate namespace

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