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Calling Protected Function From Derived Friend Function

score 160 · Answer 1 · 2015-06-10 21:57:52

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Calling Protected Function From Derived Friend Function

160 views Asked by AndrewCox At 10 June 2015 at 21:57

score 86 · Answer 2 · 2015-06-11 08:18:12

Trying to befriend a function of Derived in Base - Why doesn't it work?

86 views Asked by Rutvik Karve At 11 June 2015 at 08:18

score 78 · Answer 3 · 2015-06-21 02:50:45

C++ Can friends classes access all of the members of its base class?

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score 106 · Answer 4 · 2015-06-23 13:44:02

I don't understand how the template function gets to be a friend of the class A::X::Y in the example in [namespace.memdef]/3 in C++14

106 views Asked by Leon At 23 June 2015 at 13:44

score 273 · Answer 5 · 2015-06-23 14:28:19

Friend lookup exception from template-id?

273 views Asked by Barry At 23 June 2015 at 14:28

score 85 · Answer 6 · 2015-06-23 06:10:29

Issue with declare friend template class

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score 68 · Answer 7 · 2015-06-25 11:40:53

Lambda expressions (C++0x) not working in C++/CLI?

68 views Asked by Robin At 25 June 2015 at 11:40

score 812 · Answer 8 · 2016-12-16 23:18:15

friend declaration specifying a default argument must be a definition error

812 views Asked by lexpro At 16 December 2016 at 23:18

score 208 · Answer 9 · 2016-12-18 07:40:36

C++ friend class of the same name in different levels of a nested namespace

208 views Asked by T. Cushman At 18 December 2016 at 07:40

score 972 · Answer 10 · 2016-12-19 01:36:56

C++ friend a function in a separate namespace

972 views Asked by AudioBubble At 19 December 2016 at 01:36

TechQA.

List Question

Calling Protected Function From Derived Friend Function

Trying to befriend a function of Derived in Base - Why doesn't it work?

C++ Can friends classes access all of the members of its base class?

I don't understand how the template function gets to be a friend of the class A::X::Y in the example in [namespace.memdef]/3 in C++14

Friend lookup exception from template-id?

Issue with declare friend template class

Lambda expressions (C++0x) not working in C++/CLI?

friend declaration specifying a default argument must be a definition error

C++ friend class of the same name in different levels of a nested namespace

C++ friend a function in a separate namespace

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