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Calling Protected Function From Derived Friend Function

score 156 · Answer 1 · 2024-12-26 06:44:09

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Calling Protected Function From Derived Friend Function

156 views Asked by AndrewCox At 26 December 2024 at 06:44

score 79 · Answer 2 · 2024-12-10 04:32:20

Trying to befriend a function of Derived in Base - Why doesn't it work?

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score 76 · Answer 3 · 2024-12-26 23:05:38

C++ Can friends classes access all of the members of its base class?

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score 104 · Answer 4 · 2024-12-26 23:13:23

I don't understand how the template function gets to be a friend of the class A::X::Y in the example in [namespace.memdef]/3 in C++14

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score 271 · Answer 5 · 2024-12-26 22:49:04

Friend lookup exception from template-id?

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score 80 · Answer 6 · 2024-12-26 22:49:03

Issue with declare friend template class

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Lambda expressions (C++0x) not working in C++/CLI?

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score 804 · Answer 8 · 2024-12-25 16:57:47

friend declaration specifying a default argument must be a definition error

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score 200 · Answer 9 · 2024-12-09 13:42:20

C++ friend class of the same name in different levels of a nested namespace

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score 968 · Answer 10 · 2024-12-26 22:52:30

C++ friend a function in a separate namespace

968 views Asked by AudioBubble At 26 December 2024 at 22:52

TechQA.

List Question

Calling Protected Function From Derived Friend Function

Trying to befriend a function of Derived in Base - Why doesn't it work?

C++ Can friends classes access all of the members of its base class?

I don't understand how the template function gets to be a friend of the class A::X::Y in the example in [namespace.memdef]/3 in C++14

Friend lookup exception from template-id?

Issue with declare friend template class

Lambda expressions (C++0x) not working in C++/CLI?

friend declaration specifying a default argument must be a definition error

C++ friend class of the same name in different levels of a nested namespace

C++ friend a function in a separate namespace

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