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Question

Why are traversals defined over Applicatives, fundamentally?

score 410 · Answer 1 · 2024-11-24 14:17:50

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Why are traversals defined over Applicatives, fundamentally?

410 views Asked by janet At 24 November 2024 at 14:17

score 282 · Answer 2 · 2022-06-09 00:01:42

What is a cocartesian comonoid, and what is a cocartesian comonoidal functor?

282 views Asked by janet At 09 June 2022 at 00:01

score 119 · Answer 3 · 2022-11-21 00:48:18

Is there a name for this higher-level "bi" version of distribute in Haskell?

119 views Asked by jacobsa At 21 November 2022 at 00:48

score 331 · Answer 4 · 2017-12-22 17:15:42

Is there such thing as a bidistributive? What function do I need here?

331 views Asked by Keith Pinson At 22 December 2017 at 17:15

score 184 · Answer 5 · 2021-07-20 00:54:03

Can ZipList be Distributive?

184 views Asked by ShapeOfMatter At 20 July 2021 at 00:54

score 287 · Answer 6 · 2018-03-26 17:27:41

How to write a Representable instance using only Distributive properties?

287 views Asked by dbanas At 26 March 2018 at 17:27

score 225 · Answer 7 · 2023-04-04 11:10:31

Is there any typeclass that defines the function from `a -> m b` to `m (a -> b)`?

225 views Asked by Hexirp At 04 April 2023 at 11:10

score 121 · Answer 8 · 2023-04-12 15:48:16

How can I get from `a -> Parser b` to `Parser (a -> b)`?

121 views Asked by ShapeOfMatter At 12 April 2023 at 15:48

score 311 · Answer 9 · 2024-11-20 14:57:54

Issue when using distributive conditional types combined with generic method

311 views Asked by Jeroen Vervaeke At 20 November 2024 at 14:57

TechQA.

List Question

Why are traversals defined over Applicatives, fundamentally?

What is a cocartesian comonoid, and what is a cocartesian comonoidal functor?

Is there a name for this higher-level "bi" version of distribute in Haskell?

Is there such thing as a bidistributive? What function do I need here?

Can ZipList be Distributive?

How to write a Representable instance using only Distributive properties?

Is there any typeclass that defines the function from `a -> m b` to `m (a -> b)`?

How can I get from `a -> Parser b` to `Parser (a -> b)`?

Issue when using distributive conditional types combined with generic method

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