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Why are traversals defined over Applicatives, fundamentally?

score 468 · Answer 1 · 2025-01-02 00:25:07

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Why are traversals defined over Applicatives, fundamentally?

468 views Asked by janet At 02 January 2025 at 00:25

score 332 · Answer 2 · 2025-01-02 00:27:09

What is a cocartesian comonoid, and what is a cocartesian comonoidal functor?

332 views Asked by janet At 02 January 2025 at 00:27

score 164 · Answer 3 · 2025-01-02 00:27:01

Is there a name for this higher-level "bi" version of distribute in Haskell?

164 views Asked by jacobsa At 02 January 2025 at 00:27

score 377 · Answer 4 · 2024-12-28 12:36:19

Is there such thing as a bidistributive? What function do I need here?

377 views Asked by Keith Pinson At 28 December 2024 at 12:36

score 233 · Answer 5 · 2025-01-02 00:21:06

Can ZipList be Distributive?

233 views Asked by ShapeOfMatter At 02 January 2025 at 00:21

score 335 · Answer 6 · 2025-01-02 00:26:42

How to write a Representable instance using only Distributive properties?

335 views Asked by dbanas At 02 January 2025 at 00:26

score 274 · Answer 7 · 2025-01-02 00:25:29

Is there any typeclass that defines the function from `a -> m b` to `m (a -> b)`?

274 views Asked by Hexirp At 02 January 2025 at 00:25

score 176 · Answer 8 · 2025-01-02 00:22:40

How can I get from `a -> Parser b` to `Parser (a -> b)`?

176 views Asked by ShapeOfMatter At 02 January 2025 at 00:22

score 363 · Answer 9 · 2025-01-02 00:27:08

Issue when using distributive conditional types combined with generic method

363 views Asked by Jeroen Vervaeke At 02 January 2025 at 00:27

TechQA.

List Question

Why are traversals defined over Applicatives, fundamentally?

What is a cocartesian comonoid, and what is a cocartesian comonoidal functor?

Is there a name for this higher-level "bi" version of distribute in Haskell?

Is there such thing as a bidistributive? What function do I need here?

Can ZipList be Distributive?

How to write a Representable instance using only Distributive properties?

Is there any typeclass that defines the function from `a -> m b` to `m (a -> b)`?

How can I get from `a -> Parser b` to `Parser (a -> b)`?

Issue when using distributive conditional types combined with generic method

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