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How do you selectively simplify arguments to each time a function is called, without evaluating the function itself?

score 849 · Answer 1 · 2024-12-26 13:30:00

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849

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How do you selectively simplify arguments to each time a function is called, without evaluating the function itself?

849 views Asked by scubed At 26 December 2024 at 13:30

score 374 · Answer 2 · 2024-12-26 13:13:14

Check for evars in a tactic that returns a value

374 views Asked by Rand00 At 26 December 2024 at 13:13

score 193 · Answer 3 · 2024-12-26 13:15:13

Proof of the application of a Substitution on a term

193 views Asked by DerMann At 26 December 2024 at 13:15

score 1213 · Answer 4 · 2024-12-26 13:02:29

Coq contradiction in hypotheses

1.2k views Asked by Alexander Boll At 26 December 2024 at 13:02

score 515 · Answer 5 · 2024-12-31 00:49:20

Simplifying Subformulas in Coq

515 views Asked by Rand00 At 31 December 2024 at 00:49

score 594 · Answer 6 · 2024-12-26 13:26:20

is there any tactic in Coq that can transform a bool expression to a Prop one?

594 views Asked by Dan Johnson At 26 December 2024 at 13:26

score 393 · Answer 7 · 2024-12-26 13:15:40

Coq error: Unable to unify "true" with "is_true (0 < a - b - 3)"

393 views Asked by Dan Johnson At 26 December 2024 at 13:15

score 428 · Answer 8 · 2024-12-26 13:30:44

If two constructor expressions of an inductive type are equal in Coq, can I do rewriting based on their corresponding arguments?

428 views Asked by Dan Johnson At 26 December 2024 at 13:30

score 131 · Answer 9 · 2024-12-26 13:26:21

Can I use destruct here given the constraint I have for index range of a list?

131 views Asked by Dan Johnson At 26 December 2024 at 13:26

score 718 · Answer 10 · 2024-12-26 13:24:31

Take a conjunction of two hypotheses and create a new hypothesis in Coq

718 views Asked by Dan Johnson At 26 December 2024 at 13:24

TechQA.

List Question

How do you selectively simplify arguments to each time a function is called, without evaluating the function itself?

Check for evars in a tactic that returns a value

Proof of the application of a Substitution on a term

Coq contradiction in hypotheses

Simplifying Subformulas in Coq

is there any tactic in Coq that can transform a bool expression to a Prop one?

Coq error: Unable to unify "true" with "is_true (0 < a - b - 3)"

If two constructor expressions of an inductive type are equal in Coq, can I do rewriting based on their corresponding arguments?

Can I use destruct here given the constraint I have for index range of a list?

Take a conjunction of two hypotheses and create a new hypothesis in Coq

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