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Haskell: Is there a simpler way to express the function (\f g x y -> f (g x) (g y))? Using Applicative ((->) r)?

score 92 · Answer 1 · 2024-03-21T04:31:16.010000

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Haskell: Is there a simpler way to express the function (\f g x y -> f (g x) (g y))? Using Applicative ((->) r)?

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TechQA.

List Question

Haskell: Is there a simpler way to express the function (\f g x y -> f (g x) (g y))? Using Applicative ((->) r)?

How can i affect all content within a tag except a specific child tag

Is there a Haskell combinator of type `(a -> a -> b) -> (b -> b -> c) -> a -> a -> c`?

Combining constraints?

Type-safely Implementing an Arbitrary Degree Blackbird Combinator (B-n Combinator)

What does Haskell's Data.Function.on do?

How to unambiguously trim a string with parser combinators?

Phi combinator in Scala

Euler function of C(n, k)

How C++ lambda move capture *this in rvalue reference member function?

How to implement a fast type inference procedure for SKI combinators in Python?

How to implement SKI combinators in Prolog?

Point-free version of g(f(x)(y))

foldl versus foldr for merge operator

Creating something similar to a Zip or CombineLatest of IObservables that does not fire all outputs when one updates

Filtering multiple fields from a form to open a report

Change Opacity of non-adjacent non-sibling non-parent div using CSS-Only Checkbox

Implementing SKI transformation

How can I extract the redundancy in this Factor word definition with dataflow combinators?

Find out all combinations in a list but cannot be duplicated

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